Take -Na homogenously distributed in water , with an initial specific activity of ! Ci/} . The half life is 15 his so to simplify just…

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Take 24Na homogenously distributed in water, with an initial specific activity of 1

μCi/g. The half life is 15 hrs so to simplify just average over the first 10 minutes of

measurement and assume that activity remains constant over the full measurement time.

Assume a very large volume

3 . Take -"Na homogenously distributed in water , with an initial specific activity of !"Ci/} . The half life is 15 his so to simplify just average over the first 10 minutes ofmeasurement and assume that activity remains constant over the full measurement time .Assume a very large volume and ( a ) Find the close at the center due to each of the betasand gammas listed for* * Na in appendix C , and the total close . Do not use the equilibriumclose constants .( b ) Repeat ( a ) using the equilibrium dose constants .( C ) Now for the volume you have in problem 2 , find the close in the center . Pay attentionto absorbed fractions . You can approximate the appropriate Men .ans .( a and b )B: 197 mead$ 1 : 486 mrad* 2: 977 mad1 3 : 1 meadtotal 1. 661 rad( C )B: 197 mrad$ 1 : 237 mradY 2: 404 mrad1 3: 0. 4 meadtotal 838 mrad