In a recent poll, 500 people were asked if they liked football, and 40% said they did. Based on this, construct a 99% confidence interval for the true population proportion of people who like football.

As in the reading, in your calculations:

–Use z = 1.645 for a 90% confidence interval

–Use z = 2 for a 95% confidence interval

–Use z = 2.576 for a 99% confidence interval.

Give your answers as decimals, to 4 decimal places.

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Consider a simple poll that is measuring the proportion of citizens that hold a particular political belief. What is a conservative, “worst case scenario” sample size if you want the margin of error to be 2.3%? Sample Size =

A population of values has a normal distribution with μ=126.6μ=126.6 and σ=27.9σ=27.9. You intend to draw a random sample of size n=214n=214.

Find the probability that a single randomly selected value is less than 126.8. P(X < 126.8) =

Find the probability that a sample of size n=214n=214 is randomly selected with a mean less than 126.8. P(¯x < 126.8) = Enter your answers as numbers accurate to 4 decimal places.

You measure 30 backpacks’ weights, and find they have a mean weight of 47 ounces. Assume the population standard deviation is 13 ounces. Based on this, what is the maximal margin of error associated with a 99% confidence interval for the true population mean backpack weight.As in the reading, in your calculations:–Use z = 1.645 for a 90% confidence interval–Use z = 2 for a 95% confidence interval–Use z = 2.576 for a 99% confidence interval.Give your answer as a decimal, to two places ounces

You measure the weight of 47 turtles, and find they have a mean weight of 32 ounces. Assume the population standard deviation is 6.9 ounces. Based on this, what is the maximal margin of error associated with a 92% confidence interval for the true population mean turtle weight.Give your answer as a decimal, to two places ounces

In a survey, 12 people were asked how much they spent on their child’s last birthday gift. The results were roughly bell-shaped with a mean of $41 and standard deviation of $18. Construct a confidence interval at a 99% confidence level.Give your answers to one decimal place. Interpret your confidence interval in the context of this problem.

In a recent poll, 500 people were asked if they liked football, and 40% said they did. Based on this, construct a 99% confideinterval for the true population proportion of people who like…