# Hi, need to submit a 500 words essay on the topic Physics.(6 marks)Where h1 and h2 refer to elevation of fluid, P1 and P2 pertain to pressures experienced by the fluid which vary inversely as the spee

Hi, need to submit a 500 words essay on the topic Physics.

(6 marks)

Where h1 and h2 refer to elevation of fluid, P1 and P2 pertain to pressures experienced by the fluid which vary inversely as the speed of the fluid given either by v1 or v2. ρ stands for the density of the fluid and Bernoulli’s equation is basically a statement of conservation of energy (relating the pressure energy, PE, and KE of a perfect fluid) that applies to conditions along a streamline.

(b) An aircraft has a mass of 4.0 × 104 kg and is in steady level flight. The area of each wing is 25 m2 and the speed of the air just below the wing is 280 m s−1. Calculate the speed of the air just above the wing. The density of air is 1.2 kg m−3. (5½ marks)

A toboggan (A) of mass 35 kg slides down an icy slope which makes an angle of 20° with the horizontal (Figure 2). The toboggan starts from rest, travels a distance of 15 m down the slope after which the slope levels out to horizontal and the toboggan immediately collides with a second toboggan (B) of mass 25 kg. The coefficient of sliding friction between a toboggan and the icy surface is 0.24 and air resistance is negligible.

c) After the collision both toboggans are moving with velocities that are in the same direction that toboggan A was moving immediately before the collision, and the speed of toboggan A is 1.4 m s−1. Calculate the speed of toboggan B immediately after the collision. (3 marks)

A trainee pilot is on a flour-bombing exercise. He is aiming to hit a target on the ground which is 15 m in diameter whilst he is flying at a speed of 45 m s−1 at a height of 98 m. Air resistance is negligible and the pilot maintains a steady speed in a straight line that passes directly over the target.

Obviously, the time it takes for the flour bomb to hit the ground would be lessened since the height is in direct proportion to the square of time. Similarly, the distance from the point above the target would be