# Create a 9 page essay paper that discusses SPSS data analysis in marketing field.we also have 154 females in the 1(X32) (N) and on average, they have 128X32 with standard deviation of 10.368 X32.The l

Create a 9 page essay paper that discusses SPSS data analysis in marketing field.

we also have 154 females in the 1(X32) (N) and on average, they have 128X32 with standard deviation of 10.368 X32.The last column shows the two groups Std error mean.

Basing on table 2, the p value of Levenes test is 0.816.In this case, this p value is greater than 0.05 the alpha. Therefore, we will have to use the middle row of the output (‘labeled Equal variances assumed.’).So we will have to assume that the variances are equal and we need to use the middle row of the output. The labeled column ‘‘t’’, provides a calculated t value. In this case the t value is 0.667 assuming equal variance. The labeled column df provides the degree of freedom related with the test. In this case we have 445 degrees of freedom. The labeled column sig (2 –tailed) provides p value related to the t test. In this case, the p value 0.816.

If p ≤ α, then reject H0.Therefore, 0.816 is not equal or less than 0.05.So we fail to reject the null hypothesis. This means that we failed to observe a difference in the reasons to choosing the restaurant between men and women.

As shown in table 3, for each dependent variable, the output shows the sample size, minimum, maximum standard deviation, standard error and confidence interval for every independent variable level (quasi)

In this case, the p value of 0.466 is greater than the 0.05. we fail to reject the null hypothesis. This means that there is limited evidence that the variances aren’t equal and the variance assumption homogeneity may fit.

The 2 value in the table above is the between groups degrees of freedom, 446 is within groups degrees of freedom,0.864 is the F ratio from the F column,0.460 is the p value and 16927.906 is within groups mean square estimate of variance.

The last task now involves whether to reject null hypothesis. In this case the p value of 0.460 is seen to be greater than the 0.05.Therefore we fail to reject the null hypothesis. This means different distances have no influence on the