Consider the equation z” = (1 + 1′). Find the value of z which satisfies this equation and which has the second smallest positive argument 9, 0 lt;…

Consider the equation z” = (1 + 1′). Find the value of z which satisfies this equation and which has the second smallest positive argument 9, 0 lt;….

Please help me answer this question! I thought the answer would be r = 2^(17/2) and theta = 17pi/4 but its wrong.

Consider the equation z” = (1 + 1′). Find the value of z which satisfies this equation and which hasthe second smallest positive argument 9, 0 < 9 < 27:. Express your answer as z = new where r: and9=

Consider the equation z” = (1 + 1′). Find the value of z which satisfies this equation and which has the second smallest positive argument 9, 0 lt;…