Consider an object with s = 12; rm cm that produces an image with s’ = 15; rm cm.

Consider an object with s = 12; rm cm that produces an image with s’ = 15; rm cm. Note that whenever you are working with a physical object, the object distance will be positive (in multiple optics setups, you will encounter “objects” that are actually images, but that is not a possibility in this problem). A positive image distance means that the image is formed on the side of the lens from which the light emerges.

As the object and image are on the same sideObject distance, u = ­ 12 cmImage distance, v = ­ 15cmThin lens equation1/v – 1/u = 1/f1/f = 1/12 ­ 1/15f = 180 / (15 ­ 12) cm = 60 cmFocal…