A 45 kg person stands on a weigh-scale (which reads in Newtons) in an elevator. What acceleration (in m/s^2) of the elevator is required so that the person’s apparent weight (i.e. the reading on the weigh-scale) is 564.0 N?
The sign of the acceleration in your answer is important, take up to be the positive (+) direction and take down to be the negative (-) direction. Answer to three significant figures.